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Toggle**NCERT Solutions For Class 6 Maths, Chapter 7, Fractions, Exercise 7.5** has total five exercise of ch 7 fractions. These exercises are related to day to day example of fractions. Exercise 7.5 is mainly about finding unknown fractions by using other given fractions.

## NCERT Solutions For Class 6 Maths, Chapter 7, Fractions, Exercise 7.5

**Q.1. Write these fractions appropriately as additions or subtractions:**

**Ans: (a) Total number of parts each rectangle has = 5**

No. of shaded parts in first rectangle = 1

∴ Fraction of shaded portion = 1/5

No. of shaded parts in second rectangle = 2

∴ Fraction of shaded portion = 2/5

No. of shaded parts in third rectangle = 3

∴ Fraction of shaded portion = 3/5

Clearly, fraction of third rectangle = Sum of the fractions first and second rectangle

Hence, $\frac{1}{5}+\frac{2}{5}=\frac{3}{5}$

**(b) Total number of parts each circle = 5**

No. of shaded parts in first circle = 5

∴ Fraction of shaded portion = 5/5

No. of shaded parts in second circle = 3

∴ Fraction of shaded portion = 3/5

No. of shaded parts in third circle = 2

∴ Fraction of shaded portion = 2/5

Clearly, fraction of third circle is the difference between the fractions first and second circles.

Hence, $\frac{5}{5}-\frac{3}{5}=\frac{2}{5}$

**(c) Total number of parts in each rectangle = 6**

No. of shaded parts in first rectangle = 2

∴ Fraction of shaded portion = 2/6

No. of shaded parts in second rectangle = 3

∴ Fraction of shaded portion = 3/6

No. of shaded parts in third rectangle = 5

∴ Fraction of shaded portion = 5/6

Clearly, fraction of third rectangle is the sum of fractions first and second rectangles.

Hence, $\frac{2}{6}+\frac{3}{6}=\frac{5}{6}$

**Q.2. Solve:**

(a) $\frac{1}{18}+\frac{1}{18}$ (b) $\frac{8}{15}+\frac{3}{15}$ (c) $\frac{7}{7}-\frac{5}{7}$ (d) $\frac{1}{22}+\frac{21}{22}$ (e) $\frac{12}{15}-\frac{7}{15}$ (f) $\frac{5}{8}+\frac{3}{8}$ (g) $1-\frac{2}{3}\left( 1=\frac{3}{3} \right)$ (h) $\frac{1}{4}+\frac{0}{4}$ (i) $3-\frac{12}{5}$

**Ans:**

**Q.3. Shubham painted $\frac{2}{3}$of the wall space in his room. His sister Madhavi helped and painted $\frac{1}{3}$of the wall space. How much did they paint together?**

**Ans: **Fraction of wall painted by Shubham = $\frac{2}{3}$

Fraction of wall painted by Madhavi = $\,\frac{1}{3}$

Total space painted by both $=\,\,\frac{2}{3}\,+\,\frac{1}{3}$ $=\frac{2+1}{3}=\frac{3}{3}=1$

Therefore, Shubham and Madhavi together painted 1 complete wall in a room.

**Q.4. Fill in the missing fractions.**

**Ans:**

**Q.5. Javed was given $\frac{5}{7}$of a basket of oranges. What fraction of oranges was left in the basket?**

**Ans: **Total = 1

Fraction of oranges given to Javed =** $\frac{5}{7}$**

Fraction of oranges left in the basket = $1-\frac{5}{7}=\,\,\frac{1}{1}-\frac{5}{7}=\frac{7-5}{7}=\frac{2}{7}$

Thus, ** $\frac{2}{7}$** oranges was left in the basket.