NCERT Solution For Class 10 Maths Chapter 6 Triangles Exercise 6.2

NCERT Solution For Class 10 Maths Chapter 6 Triangles Exercise 6.2

NCERT Solution For Class 10, Maths, Chapter 6 Triangles, Exercise 6.2 consist of total ten questions which are based on properties of triangles. In class 9, we have already discussed these properties. Class 10, maths, students should have knowledge all properties and then apply them. Class 10, maths chapter 6, ex. 6.2 is given below.

Class 10, Maths, Chapter 6, Exercise 6.2 Solutions

Q.1. In Figure, (i) and (ii), DE || BC. Find EC in (i) and AD in (ii)

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Q.2. E and F are points on the sides PQ and PR respectively of a Δ PQR. For each of the following cases, state whether EF || QR:

(i) PE = 3.9 cm, EQ = 3 cm, PF = 3.6 cm and FR = 2.4 cm

(ii) PE = 4 cm, QE = 4.5 cm, PF = 8 cm and RF = 9 cm

(iii) PQ = 1.28 cm, PR = 2.56 cm, PE = 0.18 cm and PF = 0.36 cm

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Q.3. In the given figure, if LM || CB and LN || CD, prove that $\frac{AM}{AB}=\frac{AN}{AD}$

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Q.4. In the given Figure, DE || AC and DF || AE. Prove that $\frac{BF}{FE}=\frac{BE}{EC}$

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Q.5. In the given Figure, DE || OQ and DF || OR. Show that EF || QR.

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Q.6. In Figure, A, B and C are points on OP, OQ and OR respectively such that AB || PQ and AC || PR. Show that BC || QR.

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Q.7. Using Theorem 6.1, prove that a line drawn through the mid-point of one side of a triangle parallel to another side bisects the third side. (Recall that you have proved it in Class IX).

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Q.8. Using Theorem 6.2, prove that the line joining the mid-points of any two sides of a triangle is parallel to the third side. (Recall that you have done it in Class IX).

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Q.9. ABCD is a trapezium in which AB || DC and its diagonals intersect each other at the point O. Show that $\frac{AO}{BO}=\frac{CO}{DO}$

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Q.10. The diagonals of a quadrilateral ABCD intersect each other at the point O such that $\frac{AO}{BO}=\frac{CO}{DO}$ ⋅ Show that ABCD is a trapezium.

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Class 10 , Maths, Chapter 6, Triangles (All exercise)