NCERT Solutions for Class 6 Maths, chapter 2, Exercise 2.3

NCERT Solutions for class 6 maths chapter 2 exercise 2.3 is all about practicing of addition, subtraction, multiplication and dividing the numbers. there may be different ways to solve them with less amount of time. Class 6 maths chapter 2 exercise 2.3 solutions are provided here in simple ways. Class 6th maths 2.3 has total 5 questions to solve. so, students can check the solutions of whole number exercise 2.3 given below.

NCERT Solutions for Class 6 Maths, chapter 2, Whole Numbers, Exercise 2.3

Q.1.Which of the following will not represent zero:

$\begin{align}
& (a)\,\,1+0 \\
& (b)\,\,0\times 0 \\
& (c)\,\,\frac{0}{2} \\
& (d)\,\,\frac{10-10}{2} \\
\end{align}$

Ans: (a) 1 + 0 = 1

Hence, it will not represent zero

(b) 0 × 0 = 0

Hence, it will represent zero

(c) 0 / 2 = 0

Hence, it will represent zero

(d) (10 – 10) /2= 0/2 = 0

Hence, it represents zero

Q.2. If the product of two whole numbers is zero, can we say that one or both of them will be zero? Justify through examples.

Ans: Yes, if we multiply any number with zero the resultant product will always be zero.

Example: 0 × 5 = 0 and 599 × 0 = 0

if both numbers are zero, then the result also be zero.

Example: 0 × 0 = 0

Yes, if the product of two whole numbers is zero, then both of them will be zero

Q.3. If the product of two whole numbers is 1, can we say that one or both of them will be 1? Justify through examples.

Ans: If the product of two whole numbers is 1, both the numbers should be equal to 1

Example: 1 × 1 = 1 But 1 × 9 = 9

Hence, it’s clear that If both numbers are 1, then the product is 1.

Q.4. Find using distributive property:

(a) 728 × 101

(b) 5437 × 1001

(c) 824 × 25

(d) 4275 × 125

(e) 504 × 35

Ans:

(a) 728 × 101

728 × (100 + 1)

= (728 × 100) + (728 × 1)

= 72800 + 728

= 73528

(b) 5437 × 1001

= 5437 × (1000 + 1)

= (5437 × 1000) + (5437 × 1)

= 5437000 + 5437

= 5442437

(c) 824 × 25

= (800 + 24) × 25

= (800 + 25 – 1) × 25

= (800 × 25) + (25 × 25) – (1 × 25)

= 20000 + 625 – 25

= 20000 + 600

= 20600

(d) 4275 × 125

= (4000 + 200 + 100 – 25) × 125

= (4000 × 125) + (200 × 125) + (100 × 125) – (25 × 125)

= 500000 + 25000 + 12500 – 3125

= 534375

(e) 504 × 35

= (500 + 4) × 35

= (500 × 35) + (4 × 35)

= 17500 + 140

= 17640

Q.5. Study the pattern :

1 × 8 + 1 = 9 ;          

12 × 8 + 2 = 98;       

123 × 8 + 3 = 987;

1234 × 8 + 4 = 9876 ;

12345 × 8 + 5 = 98765;

Write the next two steps. Can you say how the pattern works?

Ans:

Chapter 2, Whole Numbers