Table of Contents

Toggle## Class 7, Maths, Chapter 6, Exercise 6.2 Solutions

**Q.1. Find the value of the unknown exterior angle x in the following diagrams:**

**Ans:**

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

∴ Exterior angle = Sum of interior opposite angles.

(i) x= 50°+70°=120°

(ii) x= 65°+ 45°=110°

(iii) x= 30° + 40° = 70°

(iv) x= 60°+60° =120°

(v) x= 50°+50° =100°

(vi) x= 60^{0} + 30^{0} = 90^{0}

**Q.2. Find the value of the unknown interior angle ‘x’ in the following figures:**

**Ans:**

We know, that Exterior angle = Sum of interior opposite angles, therefore

**(i) x + 50° =115°**

⟹ x =115°- 50° = 65°

**(ii) 70° + x = 100°**

⟹ x =100°- 70° = 30°

**(iii) x + 90° = 125°**

⟹ x =125°- 90° = 35°

**(iv) 60° + x = 120°**

⟹ x =120°- 60° = 60°

** (v) 30° + x = 80°**

⟹ x = 80°- 30° = 50°

**(vi) x + 35° = 75°**

⟹ x =75°- 35° = 40°

## NCERT Solutions For Class 7 Maths, Chapter 6, The Triangle and its Properties (All Exercises)

**Class 7, Maths, Chapter 6, The Triangle and Its Properties **

**Class 7, Maths, Chapter 6, The Triangle and Its Properties, Exercise 6.1**

**Class 7, Maths, Chapter 6, The Triangle and Its Properties, Exercise 6.2** **← You are here**

**Class 7, Maths, Chapter 6, The Triangle and Its Properties, Exercise 6.3**

**Class 7, Maths, Chapter 6, The Triangle and Its Properties, Exercise 6.4**

**Class 7, Maths, Chapter 6, The Triangle and Its Properties, Exercise 6.5**