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ToggleClass 7, Maths, Chapter 6, Exercise 6.2 Solutions
Q.1. Find the value of the unknown exterior angle x in the following diagrams:
Ans:
An exterior angle of a triangle is equal to the sum of its interior opposite angles.
∴ Exterior angle = Sum of interior opposite angles.
(i) x= 50°+70°=120°
(ii) x= 65°+ 45°=110°
(iii) x= 30° + 40° = 70°
(iv) x= 60°+60° =120°
(v) x= 50°+50° =100°
(vi) x= 600 + 300 = 900
Q.2. Find the value of the unknown interior angle ‘x’ in the following figures:
Ans:
We know, that Exterior angle = Sum of interior opposite angles, therefore
(i) x + 50° =115°
⟹ x =115°- 50° = 65°
(ii) 70° + x = 100°
⟹ x =100°- 70° = 30°
(iii) x + 90° = 125°
⟹ x =125°- 90° = 35°
(iv) 60° + x = 120°
⟹ x =120°- 60° = 60°
(v) 30° + x = 80°
⟹ x = 80°- 30° = 50°
(vi) x + 35° = 75°
⟹ x =75°- 35° = 40°
NCERT Solutions For Class 7 Maths, Chapter 6, The Triangle and its Properties (All Exercises)
Class 7, Maths, Chapter 6, The Triangle and Its Properties
Class 7, Maths, Chapter 6, The Triangle and Its Properties, Exercise 6.1
Class 7, Maths, Chapter 6, The Triangle and Its Properties, Exercise 6.2 ← You are here
Class 7, Maths, Chapter 6, The Triangle and Its Properties, Exercise 6.3
Class 7, Maths, Chapter 6, The Triangle and Its Properties, Exercise 6.4
Class 7, Maths, Chapter 6, The Triangle and Its Properties, Exercise 6.5