NCERT Solutions For Class 7 Maths Chapter 4 Simple Equations Exercise 4.3

Class 7, Maths, Chapter 4, Exercise 4.3 Solutions

Q.1. Solve the following equations:

(a)  $\mathrm{2y+}\frac{\mathrm{5}}{\mathrm{2}}\mathrm{=}\frac{\mathrm{37}}{\mathrm{2}}$

(b) 5t + 28 = 10

(c) $\frac{a}{5}\mathrm{+3=2}$

(d) $\frac{\mathrm{q}}{\mathrm{4}}\mathrm{+7=5}$

(e) $\frac{\mathrm{5}}{\mathrm{2}}\mathrm{x=-5}$

(f) $\frac{\mathrm{5}}{\mathrm{2}}\mathrm{x=}\frac{\mathrm{25}}{\mathrm{4}}$

(g) $\mathrm{7m+}\frac{\mathrm{19}}{\mathrm{2}}\mathrm{=13}$

(h) 6z+10=-2

(i) $\frac{\mathrm{3l}}{\mathrm{2}}\mathrm{=}\frac{\mathrm{2}}{\mathrm{3}}$

(j) $\frac{\mathrm{2b}}{\mathrm{3}}\mathrm{-5=3}$

NCERT Solutions For Class 7 Maths Chapter 4, Simple Equations, Exercise 4.3 Q.1 (a to c)

NCERT Solutions For Class 7 Maths Chapter 4, Simple Equations, Exercise 4.3 Q.1 (d to f)

NCERT Solutions For Class 7 Maths Chapter 4, Simple Equations, Exercise 4.3 Q.1 (g to i)

NCERT Solutions For Class 7 Maths Chapter 4, Simple Equations, Exercise 4.3 Q.1 (j)

Q.2. Solve the following equations:

(a) 2(x+4)=12

(b) 3(n –5)=21

(c) 3(n –5)= – 21

(d) -4(2+x)=8

(e) 4(2-x)=8

NCERT Solutions For Class 7 Maths Chapter 4, Simple Equations, Exercise 4.3 Q.2 (a to c)

NCERT Solutions For Class 7 Maths Chapter 4, Simple Equations, Exercise 4.3 Q.2 (d to e)

Q.3. Solve the following equations:

(a) 4 = 5(p – 2)

(b) – 4 = 5(p – 2)

(c) 16 = 4 + 3(t + 2)

(d) 4 + 5(p – 1) =34

(e) 0 = 16 + 4(m – 6)

NCERT Solutions For Class 7 Maths Chapter 4, Simple Equations, Exercise 4.3 Q.3 a

NCERT Solutions For Class 7 Maths Chapter 4, Simple Equations, Exercise 4.3 Q.3 b

NCERT Solutions For Class 7 Maths Chapter 4, Simple Equations, Exercise 4.3 Q.3 c

NCERT Solutions For Class 7 Maths Chapter 4, Simple Equations, Exercise 4.3 Q.3 d

NCERT Solutions For Class 7 Maths Chapter 4, Simple Equations, Exercise 4.3 Q.3 e

Q.4. (a) Construct 3 equations starting with x = 2

(b) Construct 3 equations starting with x = – 2

Ans:

(a) Construct 3 equations starting with x = 2

(i) Adding both sides 2, we get

⟹        x+2=2+2    

⟹        x+2=4

(ii) subtracting both sides by 2, we get

⟹        x-2=2-2     

⟹        x-2=0

(iii) Multiplying both sides by 2, we get

⟹        x×2=2×2    

⟹        2x=4

(b) Construct 3 equations starting with x = – 2

(i) subtracting both sides 3, we get

⟹        x-3=-2-3   

⟹        x-3=-5

(ii) Multiplying both sides by 2, we get

⟹        x×2=-2×2   

⟹        2x=-4

(iii) Multiplying both sides by 3, we get

⟹        x×3=-2×3   

⟹        3x=-6

NCERT Solutions For Class 7 Maths, Chapter 4, Simple Equations (All Exercises)