Table of Contents

Toggle## Class 7, Maths, Chapter 10, Exercise 10.3 Solutions

**Q.1. Construct ∆DEF such that DE = 5 cm, DF = 3 cm and m****∠****EDF = 90°.**

**Ans:**

**Steps of construction:**

(a) Draw a line segment DF = 3 cm.

(b) At point D, draw a ray DX to making an angle of 90^{o} i.e. ∠XDF = 90^{o}.

(c) Taking D as centre, draw an arc of radius 5 cm, which cuts DX at the point E.

(d ) Join EF.

Then, It is the required right angled triangle ΔDEF.

**Q.2. Construct an isosceles triangle in which the lengths of each of its equal sides is 6.5 cm and the angle between them is 110°.**

**Ans:**

**Steps of construction:**

- Draw a line segment AB = 6.5 cm.
- At point A, draw a ray AX to making an angle of 110
^{o}i.e. ∠XAB = 110^{o}. - Taking A as centre, draw an arc with radius 6.5 cm, which cuts AX at point C.
- Join CB.

Then, ΔABC is the required isosceles triangle.

**Q.3. Construct ∆ABC with BC = 7.5 cm, AC = 5 cm and m****∠****C = 60°.**

**Ans: **

**Steps of construction:**

- Draw a line segment BC = 7.5 cm.
- At point C, draw an angle of 60° with the help of protractor, i.e. ∠XCB = 60
^{o}. - Taking C as centre and radius 5 cm, draw an arc, which cuts XC at point A.
- Join AB.

Then, ΔABC is the required triangle.

## NCERT Solutions For Class 7 Maths, Chapter 10, Practical Geometry (All Exercises)

**Class 7, Maths, Chapter 9, Practical Geometry **

**Class 7, Maths, Chapter 9, Practical Geometry, Exercise 10.1**

**Class 7, Maths, Chapter 9, Practical Geometry, Exercise 10.2**

**Class 7, Maths, Chapter 9, Practical Geometry, Exercise 10.3** **← You are here**

**Class 7, Maths, Chapter 9, Practical Geometry, Exercise 10.4**

**Class 7, Maths, Chapter 9, Practical Geometry, Exercise 10.5**