NCERT Solutions For Class 9 Maths Chapter 9 Areas Of Parallelograms And Triangles Exercise 9.3

Class 9 Maths Chapter 9 Exercise 9.3 Solutions

Q.1. In Figure, E is any point on median AD of a Δ ABC. Show that ar (ABE) = ar (ACE).

NCERT Solutions For Class 9, Maths, Chapter 9, Exe 9.3 Q.1

Q.2. In a triangle ABC, E is the mid-point of median AD. Show that ar (BED) = $\frac{1}{4}$ ar (ABC)

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NCERT Solutions For Class 9, Maths, Chapter 9, Exe 9.3 Q.2

Q.3. Show that the diagonals of a parallelogram divide it into four triangles of equal area.

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NCERT Solutions For Class 9, Maths, Chapter 9, Exe 9.3 Q.3

Q.4. In Figure, ABC and ABD are two triangles on the same base AB. If line- segment CD is bisected by AB at O, show that ar(ABC) = ar (ABD).

NCERT Solutions For Class 9, Maths, Chapter 9, Exe 9.3 Q.4

Q.5. D, E and F are respectively the mid-points of the sides BC, CA and AB of a Δ ABC. Show that

(i) BDEF is a parallelogram.        

(ii) ar (DEF) =  ar (ABC)                

(iii) ar (BDEF) =  ar (ABC)

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NCERT Solutions For Class 9, Maths, Chapter 9, Exe 9.3 Q.5

Q.6. In Figure, diagonals AC and BD of quadrilateral ABCD intersect at O such that OB = OD. If AB = CD, then show that:

(i) ar (DOC) = ar (AOB)

(ii) ar (DCB) = ar (ACB)

(iii) DA || CB or ABCD is a parallelogram.

[Hint : From D and B, draw perpendiculars to AC.]

NCERT Solutions For Class 9, Maths, Chapter 9, Exe 9.3 Q.6

Q.7. D and E are points on sides AB and AC respectively of Δ ABC such that ar (DBC) = ar (EBC). Prove that DE || BC.

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NCERT Solutions For Class 9, Maths, Chapter 9, Exe 9.3 Q.7

Q.8. XY is a line parallel to side BC of a triangle ABC. If BE || AC and CF || AB meet XY at E and F respectively, show that ar (ABE) = ar (ACF)

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NCERT Solutions For Class 9, Maths, Chapter 9, Exe 9.3 Q.8

Q.9. The side AB of a parallelogram ABCD is produced to any point P. A line through A and parallel to CP meets CB produced at Q and then parallelogram PBQR is completed (see Fig. 9.26). Show that ar (ABCD) = ar (PBQR).

NCERT Solutions For Class 9, Maths, Chapter 9, Exe 9.3 Q.9

Q.10. Diagonals AC and BD of a trapezium ABCD with AB || DC intersect each other at O. Prove that ar (AOD) = ar (BOC).

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NCERT Solutions For Class 9, Maths, Chapter 9, Exe 9.3 Q.10

Q.11. In Figure, ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show

that (i) ar (ACB) = ar (ACF)

(ii) ar (AEDF) = ar (ABCDE)

NCERT Solutions For Class 9, Maths, Chapter 9, Exe 9.3 Q.11

Q.12. A villager Itwaari has a plot of land of the shape of a quadrilateral. The Gram Panchayat of the village decided to take over some portion of his plot from one of the corners to construct a Health Centre. Itwaari agrees to the above proposal with the condition that he should be given equal amount of land in lieu of his land adjoining his plot so as to form a triangular plot. Explain how this proposal will be implemented.

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NCERT Solutions For Class 9, Maths, Chapter 9, Exe 9.3 Q.12 

Q.13. ABCD is a trapezium with AB || DC. A line parallel to AC intersects AB at X and BC at Y. Prove that ar (ADX) = ar (ACY).     [Hint : Join CX.]

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NCERT Solutions For Class 9, Maths, Chapter 9, Exe 9.3 Q.13

Q. 14. In Figure, AP || BQ || CR. Prove that ar (AQC) = ar (PBR).

NCERT Solutions For Class 9, Maths, Chapter 9, Exe 9.3 Q.14

Q.15. Diagonals AC and BD of a quadrilateral ABCD intersect at O in such a way that ar (AOD) = ar (BOC). Prove that ABCD is a trapezium.

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NCERT Solutions For Class 9, Maths, Chapter 9, Exe 9.3 Q.15

Q.16. In Figure, ar (DRC) = ar (DPC) and ar (BDP) = ar (ARC). Show that both the quadrilaterals ABCD and DCPR are trapeziums.

NCERT Solutions For Class 9, Maths, Chapter 9, Exe 9.3 Q.16

NCERT Solutions For Class 9 Maths Chapter 9, Areas Of Parallelograms And Triangles (All Exercises)