NCERT Solutions For Class 9, Maths, Chapter 10, Circles, Exercise 10.5

NCERT Solutions For Class 9, Maths, Chapter 10, Circles, Exercise 10.5

NCERT Solutions For Class 9, Maths, Chapter 10, Circles, Exercise 10.5 is another important exercise to study. This exercise involves basically twelve exercise to discuss which are given below.

Class 9, Maths, Chapter 10, Exercise 10.5, Solutions

Q.1. In Figure, A,B and C are three points on a circle with centre O such that ∠ BOC = 30° and ∠ AOB = 60°. If D is a point on the circle other than the arc ABC, find ∠ADC.

Ans:

Q.2. A chord of a circle is equal to the radius of the circle. Find the angle subtended by the chord at a point on the minor arc and also at a point on the major arc.

Ans:

Q. 3. In Figure, ∠ PQR = 100°, where P, Q and R are points on a circle with centre O. Find ∠ OPR.

Q. 5. In Figure, A, B, C and D are four points on a circle. AC and BD intersect at a point E such that ∠ BEC = 130° and ∠ ECD = 20°. Find ∠ BAC.

Ans:

Q. 6. ABCD is a cyclic quadrilateral whose diagonals intersect at a point E. If ∠DBC = 70°, ∠BAC is 30°, find ∠BCD. Further, if AB = BC, find ∠ ECD. Ans:

Q. 7. If diagonals of a cyclic quadrilateral are diameters of the circle through the vertices of the quadrilateral, prove that it is a rectangle. Ans:

Q. 8. If the non-parallel sides of a trapezium are equal, prove that it is cyclic. Ans:

Q. 9. Two circles intersect at two points B and C. Through B, two line segments ABD and PBQ are drawn to intersect the circles at A, D and P, Q respectively (see Figure). Prove that ∠ ACP = ∠ QCD.

Ans:

Q. 10. If circles are drawn taking two sides of a triangle as diameters, prove that the point of intersection of these circles lie on the third side. Ans:

Q. 11. ABC and ADC are two right triangles with common hypotenuse AC. Prove that ∠CAD = ∠CBD.

Ans:

Q.12. Prove that a cyclic parallelogram is a rectangle.

Ans:

NCERT Solutions For Class 9 Maths Chapter 10, Circles (All Exercises)