NCERT Solution For Class 9, Maths, Chapter 2, Polynomials, Exercise 2.2 NCERT Solution For Class 9, Maths, Chapter 2, Polynomials, Exercise 2.2 has four questions to discuss Table of Contents Toggle Class 9, Maths, Chapter 2, Exercise 2.2, SolutionsNCERT Solutions For Class 9, Maths, Chapter 2, Polynomials (All Exercises) Class 9, Maths, Chapter 2, Exercise 2.2, Solutions Q.1. Find the value of the polynomial 5x – 4x^{2} + 3 at(i) x = 0(ii) x = –1(iii) x = 2Ans: Q.2. Find p(0), p(1) and p(2) for each of the following polynomials:(i) p(y) = y^{2} – y + 1(ii) p(t) = 2 + t + 2t^{2} – t^{3}(iii) p(x) = x^{3}(iv) p(x) = (x – 1) (x + 1)Ans: Q.3. Verify whether the following are zeroes of the polynomial, indicated against them.(i) p(x) = 3x + 1, x = $-\frac{1}{3}$(ii) p(x) = 5x – 4, x = $\frac{4}{5}$(iii) p(x) = x^{2} -1, x = 1, – 1(iv) p(x)=(x+1)(x-2), x= -1, 2(v) p(x) = x^{2}, x = 0(vi) p(x) = lx + m, x = $-\frac{m}{l}$(vii) p(x) = 3x^{2} – 1, x = $-\frac{1}{\sqrt{3}},\frac{2}{\sqrt{3}}$ (viii) p(x) = 2x + 1, x = $\frac{1}{2}$Ans: Q.4. Find the zero of the polynomials in each of the following cases:(i) p(x) = x + 5 (ii) p(x) = x – 5 (iii) p(x) = 2x + 5(iv) p(x) = 3x – 2 (v) p(x) = 3x (vi) p(x) = ax, a ≠ 0(vii) p(x) = cx + d, c ≠ 0, c, d are real numbers.Ans: NCERT Solutions For Class 9, Maths, Chapter 2, Polynomials (All Exercises) Class 9, Maths, Chapter 2, Polynomials, Exercise 2.1Class 9, Maths, Chapter 2, Polynomials, Exercise 2.2Class 9, Maths, Chapter 2, Polynomials, Exercise 2.3Class 9, Maths, Chapter 2, Polynomials, Exercise 2.4Class 9, Maths, Chapter 2, Polynomials, Exercise 2.5