NCERT Solutions For Class 8 Maths Chapter 1 Rational Numbers Exercise 1.1

Class 8, Maths, Chapter 1, Exercise 1.1, Solutions

Q.1. Using appropriate properties find.

NCERT Solutions Class 8 Ch.1, Ex.1.1 q.1

Q.2. Write the additive inverse of each of the following

(i) $\frac{2}{8}$

(ii) $\frac{-5}{9}$

(iii) $\frac{-6}{-5}$

(iv) $\frac{2}{-9}$

(v) $\frac{19}{-6}$

Ans:

(i) $\frac{2}{8}$

$\frac{2}{8}\Rightarrow \frac{-2}{8}$

(ii) $\frac{-5}{9}$

$\frac{-5}{9}\Rightarrow \frac{5}{9}$

(iii) $\frac{-6}{-5}$

$\frac{-6}{-5}\Rightarrow \frac{6}{5}$

(iv) $\frac{2}{-9}$

$\frac{2}{-9}\Rightarrow \frac{2}{9}$

(v) $\frac{19}{-6}$

$\frac{19}{-6}\Rightarrow \frac{19}{6}$

Q.3. Verify that – (– x) = x for.

(i) $x=\frac{11}{15}$

(ii) $x=-\frac{13}{17}$

NCERT Solutions Class 8 Ch.1, Ex.1.1 q.3

Q.4. Find the multiplicative inverse of the following.

(i) -13

(ii) $\frac{-13}{19}$

(iii) $\frac{1}{5}$

(iv)  $\frac{-5}{8}\times \frac{-3}{7}$

(v) $-1\times \frac{-2}{5}$

(vi) -1

Ans: We know that multiplicative inverse of x is $\frac{1}{x}$

(i) -13

$-13\Rightarrow \frac{1}{-13}$

(ii) $\frac{-13}{19}$

    $\frac{-13}{19}\Rightarrow \frac{-19}{13}$

(iii) $\frac{1}{5}$

$\frac{1}{5}\Rightarrow \frac{5}{1}$

(iv)  $\frac{-5}{8}\times \frac{-3}{7}$

$\frac{-5}{8}\times \frac{-3}{7}=\frac{-8}{5}\times \frac{-7}{3}=\frac{56}{15}$

Alternatively,

    $\frac{\mathsf{-5}}{\mathsf{8}}\mathsf{\times }\frac{\mathsf{-3}}{\mathsf{7}}\mathsf{=}\frac{\mathsf{(-5)\times (-3)}}{\mathsf{8\times 7}}\mathsf{=}\frac{\mathsf{15}}{\mathsf{56}}\Rightarrow \frac{\mathsf{56}}{\mathsf{15}}$

(v) $-1\times \frac{-2}{5}$

$-1\times \frac{-2}{5}=\frac{\left( -1 \right)\times \left( -2 \right)}{5}=\frac{2}{5}\Rightarrow \frac{5}{2}$

(vi) -1

The multiplicative of -1 is -1. 

-1 -1

Q.5. Name the property under multiplication used in each of the following.

(i) $\frac{-4}{5}\times 1=1\times \frac{-4}{5}=-\frac{4}{5}$

(ii) $-\frac{13}{17}\times \frac{-2}{7}=\frac{-2}{7}\times \frac{-13}{17}$

(iii) $-\frac{19}{29}\times \frac{29}{-19}=1$

Ans:

(i) $\frac{-4}{5}\times 1=1\times \frac{-4}{5}=-\frac{4}{5}$

1 is the multiplicative identity.

(ii) $-\frac{13}{17}\times \frac{-2}{7}=\frac{-2}{7}\times \frac{-13}{17}$

since,   a x b = b x a

therefore, it is commutatively.

(iii) $-\frac{19}{29}\times \frac{29}{-19}=1$

Multiplicative inverse.

Q.6. Multiply $\frac{6}{13}$ by the reciprocal of $\frac{-7}{16}$.

NCERT Solutions Class 8 Ch.1, Ex.1.1 q.6

Q.7. Tell what property allows you to compute $\frac{1}{3}\times \left( 6\times \frac{4}{3} \right)\ $ as $\left( \frac{1}{3}\times 6 \right)\times \frac{4}{3}\ $.

NCERT Solutions Class 8 Ch.1, Ex.1.1 q.7

Q.8. Is $\frac{8}{9}$ the multiplicative inverse of $-1\frac{1}{8}$ ? Why or why not?

NCERT Solutions Class 8 Ch.1, Ex.1.1 q.8

Q.9. Is 0.3 the multiplicative inverse of $3\frac{1}{3}$.? Why or why not?

NCERT Solutions Class 8 Ch.1, Ex.1.1 q.9

Q.10. Write.

(i) The rational number that does not have a reciprocal.

(ii) The rational numbers that are equal to their reciprocals.

(iii) The rational number that is equal to its negative.

Ans:

(i) The rational number that does not have a reciprocal. = zero,

(ii) The rational numbers that are equal to their reciprocals. = 1, -1

(iii) The rational number that is equal to its negative. = 0

Q.11. Fill in the blanks.

(i) Zero has ________ reciprocal.

(ii) The numbers ________ and ________ are their own reciprocals

(iii) The reciprocal of – 5 is ________.

(iv) Reciprocal of $\frac{1}{x}$, where x ≠ 0 is ________.

(v) The product of two rational numbers is always a _______.

(vi) The reciprocal of a positive rational number is ________.

Ans:

(i)  No

(ii) 1, -1

(iii) $-\frac{1}{5}$

(iv) x

(v) rational numbers

(vi) positive numbers.

NCERT Solutions For Class 8 Maths Chapter 1, Rational Numbers (All Exercises)