NCERT Solutions For Class 6 Maths, Chapter 7, Fractions, Exercise 7.5

NCERT Solutions For Class 6 Maths, Chapter 7, Fractions, Exercise 7.5 has total five exercise of ch 7 fractions. These exercises are related to day to day example of fractions. Exercise 7.5 is mainly about finding unknown fractions by using other given fractions.  

NCERT Solutions For Class 6 Maths, Chapter 7, Fractions, Exercise 7.5

Q.1. Write these fractions appropriately as additions or subtractions:

NCERT Solutions for Class 6 Maths, Chapter 7, Fractions, Exercise 7.5 q.

Ans: (a) Total number of parts each rectangle has = 5

       No. of shaded parts in first rectangle = 1

∴                  Fraction of shaded portion = 1/5            

       No. of shaded parts in second rectangle = 2

∴                  Fraction of shaded portion = 2/5

       No. of shaded parts in third rectangle = 3

∴                  Fraction of shaded portion = 3/5

Clearly, fraction of third rectangle = Sum of the fractions  first and second rectangle

Hence,         $\frac{1}{5}+\frac{2}{5}=\frac{3}{5}$

(b) Total number of parts each circle  = 5

       No. of shaded parts in first circle = 5

∴                  Fraction of shaded portion = 5/5      

       No. of shaded parts in second circle = 3

∴                  Fraction of shaded portion = 3/5      

       No. of shaded parts in third circle = 2

∴                  Fraction of shaded portion = 2/5      

Clearly, fraction of third circle is the difference between the fractions first and second circles.

Hence,           $\frac{5}{5}-\frac{3}{5}=\frac{2}{5}$

(c) Total number of parts in each rectangle  = 6

       No. of shaded parts in first rectangle = 2

∴                  Fraction of shaded portion = 2/6

       No. of shaded parts in second rectangle = 3

∴                  Fraction of shaded portion = 3/6

       No. of shaded parts in third rectangle = 5

∴                  Fraction of shaded portion = 5/6

Clearly, fraction of third rectangle is the sum of fractions first and second rectangles.

Hence,        $\frac{2}{6}+\frac{3}{6}=\frac{5}{6}$

 

Q.2. Solve:

(a) $\frac{1}{18}+\frac{1}{18}$    (b) $\frac{8}{15}+\frac{3}{15}$   (c) $\frac{7}{7}-\frac{5}{7}$   (d) $\frac{1}{22}+\frac{21}{22}$   (e) $\frac{12}{15}-\frac{7}{15}$   (f) $\frac{5}{8}+\frac{3}{8}$   (g) $1-\frac{2}{3}\left( 1=\frac{3}{3} \right)$  (h) $\frac{1}{4}+\frac{0}{4}$   (i) $3-\frac{12}{5}$

Ans:

NCERT Solutions for Class 6 Maths, Chapter 7, Fractions, Exercise 7.5 q.1

Q.3. Shubham painted  $\frac{2}{3}$of the wall space in his room. His sister Madhavi helped and painted $\frac{1}{3}$of the wall space. How much did they paint together?

Ans: Fraction of wall painted by Shubham =  $\frac{2}{3}$

Fraction of wall painted by Madhavi =  $\,\frac{1}{3}$

Total space painted by both $=\,\,\frac{2}{3}\,+\,\frac{1}{3}$ $=\frac{2+1}{3}=\frac{3}{3}=1$

Therefore,  Shubham and Madhavi together painted 1 complete wall in a room.

Q.4. Fill in the missing fractions.

NCERT Solutions for Class 6 Maths, Chapter 7, Fractions, Exercise 7.5 q.4

Ans:

NCERT Solutions for Class 6 Maths, Chapter 7, Fractions, Exercise 7.5 q.4

NCERT Solutions for Class 6 Maths, Chapter 7, Fractions, Exercise 7.5 q.4

NCERT Solutions for Class 6 Maths, Chapter 7, Fractions, Exercise 7.5 q.4

NCERT Solutions for Class 6 Maths, Chapter 7, Fractions, Exercise 7.5 q.4

Q.5. Javed was given $\frac{5}{7}$of a basket of oranges. What fraction of oranges was left in the basket?

Ans: Total = 1

Fraction of oranges given to Javed = $\frac{5}{7}$

Fraction of oranges left in the basket =  $1-\frac{5}{7}=\,\,\frac{1}{1}-\frac{5}{7}=\frac{7-5}{7}=\frac{2}{7}$

Thus, $\frac{2}{7}$ oranges was left in the basket.

Chapter 7, Fractions