NCERT Solution For Class 6, Maths, Chapter 1, Knowing Our Numbers, Exercise 1.2 consist of total 12 exercise to study. Chapter 1, exercise 1.2 solution given below.
NCERT Solution For Class 6, Maths, Chapter 1, Knowing Our Numbers, Exercise 1.2
Q.1. A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third and final day was respectively 1094, 1812, 2050 and 2751. Find the total number of tickets sold on all the four days.
Ans: Number of tickets sold on first day = 1,094
Number of tickets sold on second day = 1,812
Number of tickets sold on third day = 2,050
Number of tickets sold on fourth day = 2,751
Total tickets sold = 1,094 + 1,812 + 2,050 + 2,751 = 7,707 tickets
Therefore, number of tickets sold on all the four days are 7,707 tickets.
Q.2. Shekhar is a famous cricket player. He has so far scored 6980 runs in test matches. He wishes to complete 10,000 runs. How many more runs does he need?
Ans: Shekhar wishes to complete = 10,000 runs
He scored = 6,980 runs
Runs need to score more = 10,000 – 6,980 = 3,020
Therefore, he needs 3,020 more runs to score.
Q.3. In an election, the successful candidate registered 5,77,500 votes and his nearest rival secured 3,48,700 votes. By what margin did the successful candidate win the election?
Ans: No. of votes secured by the successful candidate = 5,77,500
No. of votes secured by his nearest rival = 3,48,700
Margin by which he won the election = 5,77,500 – 3,48,700 = 2,28,800 votes
Therefore, successful candidate won the election by a margin of 2,28,800 votes.
Q.4. Kirti bookstore sold books worth ₹ 2,85,891 in the first week of June and books worth ₹ 4,00,768 in the second week of the month. How much was the sale for the two weeks together? In which week was the sale greater and by how much?
Ans: Price of books sold in June first week = Rs 2,85,891
Price of books sold in June second week = Rs 4,00,768
Total books sold = Rs 2,85,891 + Rs 4,00,768 = Rs 6,86,659
Since, 4,00,768 > 2,85,891
The sale of books is the highest in the second week.
Difference in the sale in both weeks = Rs 4,00,768 – Rs 2,85,891 = Rs 1,14,877
Therefore, books of Rs 1,14,877 were more sold in second week.
Q.5. Find the difference between the greatest and the least 5-digit number that can be written using the digits 6, 2, 7, 4, 3 each only once.
Ans: Digits given are 6, 2, 7, 4, 3
Greatest five-digit number using digits 6,2,7,4,3 = 76432
Smallest or Least five-digit number = 23467
Difference between the two numbers = 76432 – 23467 = 52965
Therefore, the difference between the two numbers is 52965.
Q.6. A machine, on an average, manufactures 2,825 screws a day. How many screws did it produce in the month of January 2006?
Ans: Number of screws manufactured in a day = 2,825
Since January month has 31 days
Hence, number of screws manufactured in January = 31 × 2,825 = 87,575
Hence, machine produce 87,575 screws in the month of January 2006.
Q.7. A merchant had ₹ 78,592 with her. She placed an order for purchasing 40 radio sets at ₹ 1200 each. How much money will remain with her after the purchase?
Ans: Order placed for purchasing = 40 radio sets
Cost of one radio set = Rs 1,200
So, cost of 40 radio sets = Rs 1,200 × 40 = Rs 48,000
Now,
Total money the merchant had = Rs 78,592
Money left after the purchasing = Rs 78,592 – Rs 48,000 = Rs 30,592
Hence, money left with the merchant after purchasing radio sets is Rs 30,592.
Q.8. A student multiplied 7236 by 65 instead of multiplying by 56. By how much was his answer greater than the correct answer? (Hint: Do you need to do both the multiplications?)
Ans: The difference between the correct and incorrect answer
= 7236 x 65 – 7236 x 56
= 7236 x (65 – 56)
= 7236 x 9
= 65124
Hence, his answer will be 65124, greater than the correct answer.
Q.9. To stitch a shirt, 2 m 15 cm cloth is needed. Out of 40 m cloth, how many shirts can be stitched and how much cloth will remain?
(Hint: convert data in cm.)
Ans: Total length of the cloth = 40 m
= 40 × 100 cm
= 4000 cm
Cloth required to stitch one shirt = 2 m 15 cm
= 2 ×100+15 cm
= 215 cm
Number of shirts that can be stitched out of 4000 cm = 4000 ÷215
Hence, 18 shirts can be stitched out of 40 m and 1m 30 cm of cloth is left out.
Q.10. Medicine is packed in boxes, each weighing 4 kg 500g. How many such boxes can be loaded in a van which cannot carry beyond 800 kg?
Ans: Maximum weight cab be loaded by the van = 800 kg
= 800 × 1000
= 800000 g
Weight of one box = 4 kg 500 g
= (4 ×1000) + 500
= 4500 g
Hence,
Number of boxes that can be loaded in the van $=\frac{800000}{4500}$
Hence, number of boxes that can be loaded in the van are 177 boxes.
Q.11. The distance between the school and a student’s house is 1 km 875 m. Every day she walks both ways. Find the total distance covered by her in six days.
Ans: Distance between school and house = 1 km 875 m
= 1000 + 875
= 1875 m
Since, the student walk both ways.
Hence, distance travelled by the student in one day = 2 × 1875 = 3750 m
Distance travelled by the student in six days = 3750 m × 6
= 22500 m
= 22 km 500 m
Therefore, 22 km 500 m distance covered in six days.
Q.12. A vessel has 4 litres and 500 ml of curd. In how many glasses, each of 25 ml capacity, can it be filled?
Ans: Quantity of curd in the vessel = 4 litre 500 ml
= (4 × 1000) + 500
= 4500 ml
Capacity of 1 glass = 25 ml
∴ Number of glasses that can be filled = 4500÷ 25
Therefore, 180 glasses can be filled with curd.