NCERT Solutions For Class 7 Maths Chapter 10 Practical Geometry Exercise 10.5

Table of Contents

Class 7, Maths, Chapter 10, Exercise 10.5 Solutions

Q.1. Construct the right angled ∆PQR, where m∠Q = 90°, QR = 8cm and PR = 10 cm.

Ans:

Steps of construction:

Draw a line segment QR = 8 cm.
At point Q, draw an angle of 90^oi.e. ∠XQR = 90^o.
With R as a center and radius 10 cm, draw an arc that cuts the ray XQ at P.
Join PR.

Then, ΔPQR is the required right angled triangle.

Q.2. Construct a right-angled triangle whose hypotenuse is 6 cm long and one of the legs is 4 cm long.

Ans:

Steps of construction:

Draw a line segment BC = 4 cm.
At point B, draw an angle of 90^oi.e. ∠XBC = 90^o.
With C as a centre and radius 6 cm, draw an arc that cuts BX at A.
Join AC.

Then, ΔABC is the required right angled triangle.

Q.3. Construct an isosceles right-angled triangle ABC, where m∠ACB = 90° and AC = 6 cm.

Ans:

Steps of construction:

Draw a line segment BC = 6 cm.
At point C, draw an angle of 90^oi.e. ∠XCB = 90^o.
With C as a center and radius 6 cm, draw an arc that cuts CX at A.
Join AB.

Then, ΔABC is the required right angled triangle.

NCERT Solutions For Class 7 Maths, Chapter 10, Practical Geometry (All Exercises)

Class 7, Maths, Chapter 9, Practical Geometry

Class 7, Maths, Chapter 9, Practical Geometry, Exercise 10.1

Class 7, Maths, Chapter 9, Practical Geometry, Exercise 10.2

Class 7, Maths, Chapter 9, Practical Geometry, Exercise 10.3

Class 7, Maths, Chapter 9, Practical Geometry, Exercise 10.4

Class 7, Maths, Chapter 9, Practical Geometry, Exercise 10.5 ← You are here