NCERT Solutions For Class 9 Maths Chapter 7 Triangles Exercise 7.3

Class 9 Maths Chapter 7 Exercise 7.3 Solutions

Q.1. Δ ABC and Δ DBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (see Figure). If AD is extended to intersect BC at P, show that

(i) Δ ABD Δ ACD

(ii) Δ ABP Δ ACP

(iii) AP bisects A as well as D.

(iv) AP is the perpendicular bisector of BC.

NCERT Solutions For Class 9, Maths, Chapter 7, Exe 7.3 Q.1 figure

Ans:

NCERT Solutions For Class 9, Maths, Chapter 7, Exe 7.3 Q.1

Q.2. AD is an altitude of an isosceles triangle ABC in which AB = AC. Show that

        (i) AD bisects BC

        (ii) AD bisects A.

Ans:

NCERT Solutions For Class 9, Maths, Chapter 7, Exe 7.3 Q.2

Q.3. Two sides AB and BC and median AM of one triangle ABC are respectively equal to sides PQ and QR and median PN of Δ PQR (see Figure). Show that:

(i) Δ ABM Δ PQN

(ii) Δ ABC Δ PQR

NCERT Solutions For Class 9, Maths, Chapter 7, Exe 7.3 Q.3

Q.4. BE and CF are two equal altitudes of a triangle ABC. Using RHS congruence rule, prove that the triangle ABC is isosceles.

Ans:

NCERT Solutions For Class 9, Maths, Chapter 7, Exe 7.3 Q.4

Q.5. ABC is an isosceles triangle with AB = AC. Draw AP BC to show that B = C.

Ans:

NCERT Solutions For Class 9, Maths, Chapter 7, Exe 7.3 Q.5

NCERT Solutions For Class 9 Maths Chapter 7, Triangles (All Exercises)