NCERT Solution For Class 9, Maths, Chapter 13, Surface Areas And Volumes, Exercise 13.9 (Optional)

NCERT Solution For Class 9, Maths, Chapter 13, Surface Areas And Volumes, Exercise 13.9 is all about day to day examples like decorative sphere, a wall etc in which we need to find required values by using suitable formula.

NCERT Solution For Class 9, Maths, Chapter 13, Surface Areas And Volumes, Exercise 13.9

Class 9, Maths, Chapter 13, Exercise 13.9 Solutions (Page no. 236)

Q.1. A wooden bookshelf has external dimensions as follows: Height = 110 cm, Depth = 25 cm, Breadth = 85 cm (see Fig. 13.31). The thickness of the plank is 5 cm everywhere. The external faces are to be polished and the inner faces are to be painted. If the rate of polishing is 20 paise per cm2 and the rate of painting is 10 paise per cm2, find the total expenses required for polishing and painting the surface of the bookshelf.

NCERT Solution For Class 9, Maths, Chapter 13, Surface Areas And Volumes, Exercise 13.9 Q. 1

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NCERT Solution For Class 9, Maths, Chapter 13, Surface Areas And Volumes, Exercise 13.9 Q. 1 Answer

Q.2. The front compound wall of a house is decorated by wooden spheres of diameter 21 cm, placed on small supports as shown in the Figure. Eight such spheres are used for this purpose, and are to be painted silver. Each support is a cylinder of radius 1.5 cm and height 7 cm and is to be painted black. Find the cost of paint required if silver paint costs 25 paise per cm2 and black paint costs 5 paise per cm2.

NCERT Solution For Class 9, Maths, Chapter 13, Surface Areas And Volumes, Exercise 13.9 Q. 2

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NCERT Solution For Class 9, Maths, Chapter 13, Surface Areas And Volumes, Exercise 13.9 Q. 2

Q.3. The diameter of a sphere is decreased by 25%. By what per cent does its curved surface area decrease?

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NCERT Solution For Class 9, Maths, Chapter 13, Surface Areas And Volumes, Exercise 13.9 Q.3

NCERT Solutions For Class 9, Maths, Chapter 13, Surface Areas And Volumes  (All Exercises)